Question

evaluate （xminus1uponx）spuare minus （x plus1uponx）spuare​

Answer 1

Answer:

$({x - \frac{1}{x})}^{2} - {(x + \frac{1}{x}) }^{2} \\ \\ {x}^{2} + \frac{1}{ {x}^{2} } - 2 - {x}^{2} - \frac{1}{ {x}^{2} } - 2 \\ \\ - 4 \: is \: ur \: answer$

Answer 2

Answer:

$0$

Step-by-step explanation:

$(x - \frac{1}{x} )^{2} - (x - \frac{1}{x} )^{2} \\ = ( {x}^{2} + { \frac{1}{x} }^{2} - 2 \times x \times \frac{1}{x} ) - ({x}^{2} + { \frac{1}{x} }^{2} - 2 \times x \times \frac{1}{2} ) \\ = ( {x}^{2} + { \frac{1}{x} }^{2} - 2) - ({x}^{2} + { \frac{1}{x} }^{2} - 2) \\ = {x}^{2} + { \frac{1}{x} }^{2} - 2 - {x}^{2} - \frac{1}{x} ^{2} + 2 \\ = 0$