evaluate (y-7 ) (y-3)
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y^2-3y+7y-21=0
y^2+4y-21=0
(y+7)(y-3)=0
y=-7 ya y=+3 Ans...
Answered by
1
(y-7)(y-3)
y^2-3y-7y+21=0
y^2-10y+21=0
y^2-7y-3y+21=0
--------- --------
y(y-7)-3(y-7)=0
(y-3)(y-7)=0
y-3=0 OR y-7=0
y=3 OR y=7
therefore 3 or 7 is the root given problem
y^2-3y-7y+21=0
y^2-10y+21=0
y^2-7y-3y+21=0
--------- --------
y(y-7)-3(y-7)=0
(y-3)(y-7)=0
y-3=0 OR y-7=0
y=3 OR y=7
therefore 3 or 7 is the root given problem
yash6989262:
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