Evaluate ∫∫ydxdy over the region
betwech the
parobola x²=y and the line x+y=2
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Step-by-step explanation:
The in tersection point of parabolas y = x2 and x = y2 is
y = ( v2)2 ⇒ y = y4
⇒y=0,y=1⇒x=0,x=1
So, the intersection point in 0(0, 0) and (1, 1).
∴ Required area = ∫10(y2−y1)dx
=∫10(x−−√−x2)dx
=[x3/23/2−x33]0=[23x3/2−x33]10
=[23(1)−13(1)+0−0]
=[23−13]=13
Alternate method
We know that, if parabolas are y2 = 4ax and x2 = 4, then area of bounded region is 4a⋅4b3
∴ Required area =1×13=13
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