Question

Evaluate Yourself 5, 4) 1 mol of PCI kept in a closed container of volume 1 dm and was allowed to attain equilibrium at 423 K. Calculate the equilibrium composition of reaction mixture. (The K value for PCI dissociation at 423 K is 2) с​

Answer 1

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Answer 2

[PCl5]eq = (1 - x) / 1 = 1 – 0.732 = 0.268 M

[PCl5]eq = (1 - x) / 1 = 1 – 0.732 = 0.268 M [PCl3]eq = x / 1 = 0.732 / 1 = 0.732

[PCl5]eq = (1 - x) / 1 = 1 – 0.732 = 0.268 M [PCl3]eq = x / 1 = 0.732 / 1 = 0.732 [Cl2]eq = x / 1= 0.732 / 1 = 0.732