Question

Evaluate Yourself
6. How many unpaired electrons are
present in the ground state of Fe3+
(z=26), Mn2+:(z=25) and argon (z=18) ​

Answer 1

Explanation:

Fe = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁶

Fe+3 in ground state= 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵

no of unpaired electrons =5

Mn= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵

Mn+2 in ground state = 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵

total no of unpaired electron = 5

Ar in ground state= 1s² 2s² 2p⁶ 3s² 3p⁶

total no of unpaired electrons = 0

Hope you understand the answers