Question

evaluate3/5+7/3+(-2/5)+(-2/3)after rearrangement

Answer 1

Given that: 3/5+7/3+(-2/5)+(-2/3)

We will write same denominators terms together:

So 3/5+(-2/5)+7/3+(-2/3)=( (3-2)/5)+((7-2)/3)= (1/5)+(5/3)

Now we will make the denominators same: so LCD of 5 and 3 is 15

So 1/5 = 3/15, 5/3= 25/15

So 1/5+5/3 = 3/15+25/15-= (3+25)/15= 28/15

So 3/5+(-2/5)+7/3+(-2/3)=28/15