CBSE BOARD X, asked by yaduvanshiastha, 6 months ago

Evalute [0.35]^3 +(0.41) ^3 - (0.76) ^3/9(0.35) (0.41) (0.76)​

Answers

Answered by jainishita1606
0

Answer:

((0.35)³+(0.41)³-(0.76)³)/0.35*0.41*0.76 = 3

Explanation:

Here's an identity: a³+b³+c³= 3 abc if a+b+c=0

Let a be 0.35
Let b be 0.41
Let c be -0.76

((0.35)³+(0.41)³-(0.76)³)/0.35*0.41*0.76 = 3
Here's an identity: a³+b³+c³= 3 abc if a+b+c=0

Let a be 0.35
Let b be 0.41
Let c be -0.76

((0.35)³+(0.41)³-(0.76)³)/0.35*0.41*0.76 = 3
Here's an identity: a³+b³+c³= 3 abc if a+b+c=0

Let a be 0.35
Let b be 0.41
Let c be -0.76

((0.35)³+(0.41)³-(0.76)³)/0.35*0.41*0.76 = 3
Here's an identity: a³+b³+c³= 3 abc if a+b+c=0

1) Let a be 0.35
2) Let b be 0.41
3) Let c be -0.76

((0.35)³+(0.41)³-(0.76)³)/0.35*0.41*0.76

= ((0.35)³+(0.41)³+ (-0.76)³)/0.35*0.41*0.76
= a³+b³+c³/abc
= 3abc/abc
= 3
(Here a+b+c= 0.35+0.41+-0.76= 0
So, a³+b³+c³= 3abc)

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