Evalute (102) ka whole cub by using dutable identities
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Answered by
3
(102)³=(100+2)³
=100³+2³+3(100)(2)(100+2) [(a+b)³=a³+b³+3ab(a+b)]
=1000000+8+600×102
=1000000+8+61200
=1061208
=100³+2³+3(100)(2)(100+2) [(a+b)³=a³+b³+3ab(a+b)]
=1000000+8+600×102
=1000000+8+61200
=1061208
Answered by
2
(100+2)whole cube
(a+b)whole cube=a cube +b cube+3ab(a+b)
100 cube+2cube+3×100×2(100+2)
1000000+8+600(102)
1000008+61200
1061208
(a+b)whole cube=a cube +b cube+3ab(a+b)
100 cube+2cube+3×100×2(100+2)
1000000+8+600(102)
1000008+61200
1061208
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