Evalute (105)whole cube
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Answered by
22
(105)³=100³+5³
=(a+b)³=a³+b³+3ab(a+b)
1000000+125+157500
1157625
=(a+b)³=a³+b³+3ab(a+b)
1000000+125+157500
1157625
Answered by
16
Algebraic Identity:
(a+b)³=a³+b³+3ab(a+b)
Break into two parts:
(105)³⇒(100+5)³
⇒(a+b)³=a³+b³+3ab(a+b)
⇒1000000+125+157500
⇒1157625
(a+b)³=a³+b³+3ab(a+b)
Break into two parts:
(105)³⇒(100+5)³
⇒(a+b)³=a³+b³+3ab(a+b)
⇒1000000+125+157500
⇒1157625
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