Question

Evalute: £•π/2 1/3+2cosx dx​

Answer 1

Answer:

Answer

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Consider the given integral.

I=∫0π/23+2cosx1dx

I=∫0π/23+2(1−2sin22x)1dx

I=∫0π/23+2−4sin22x1dx

I=∫0π/25sec22x−4tan22xsec22xdx

I=∫0π/25(tan22x+1)−4tan22x