Question

Evalute 2cos67÷sin23-tan40÷cot50-cos0​

Answer 1

Answer:

1

will be your answer you should apply formula

sinA=cos (90-A)

Answer 2

0

Step-by-step explanation:

2(cos67/sin23)-(tan40/cot50)-cos0

2(sin23/sin23)-(tan40/tan50)-1

2-1-1

=0

i think this ans will help u