Question

evalute: (3)^0+(4)^3+(-2/3)^0​

Answer 1

Answer:

(3)^0+(4)^3+(-2/3)^0

= 1+64+1

= 66

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Answer 2

Answer:

$( {3})^{0} + ( {4})^{3} + ( \frac{ - 2}{3} ) ^{0} \\ \\ = 1 + 64 + 1 \\ \\ = 66 \\ \\ remember \\ \\ any \: number \: to \: the \: power \: 0 \\ is \: always \: 1$

hope it helps