Question

Evalute : 3x (4x-5)+ 3 when x= 1/
2​

Answer 1

Answer:

surprised no one answered you sine yesterday

Step-by-step explanation:

if x = 1/2 then;

3(1/2)[4(1/2) - 5] + 3

3/2(2-5)+3

3/2(-3)+3

-9/2+3 = -9+6/2 = -3/2

I'd rather solve it with decimal

x=0.5

3(0.5)[4(0.5)-5]+3

1.5[2-5]+3

(1.5*-3)+3

-4.5+3

= -1.5 (same as -3/2)

Please mark me as brainiest. Thanks!