Question

Evalute 5+ (1+ tan^2 theta) sin theta cos theta/ tan theta​

Answer 1

Answer:

thank you souvik

Step-by-step explanation:

I hope you are seeing this question

answer is

L.H.S.=

2cos

2

θ

(cosθ−sinθ)(1+tanθ)

=

cosθ(2cos

2

θ−1)

(cosθ−sinθ)(cosθ+sinθ)

=

cosθ(2cos

2

θ−1)

cos

2

θ−sin

2

θ

=

cosθ(2cos

2

θ−1)

cos

2

θ−(1−cos

2

θ)

=

cosθ(2cos

2

θ−1)

cos

2

θ−1+cos

2

θ

=

cosθ(2cos

2

θ−1)

2cos

2

θ−1

=

cosθ

1

=secθ=R.H.S.

Answer 2

Answer:

5+(1+tan^2)sin theta cos theta/tan theta

5+(1/cos^2)sin X cos/tan

5+ (Sin/cos)/tan

5+1=6