Question

evalute a^x-y.a^y-x. a^z-x
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Answer 1

Answer:

i guess the question is wrong. it is supposed to be$a^{x-y}.a^{y-z}.a^{z-x}$

then the answer is,

$a^{x-y+y-z+z-x}$ = $a^{0}$ = 1

according to your question, the answer is,

$a^{x-y}.a^{y-x}.a^{z-x}$

since the bases are equal,

∴$a^{x-y+y-x+z-x}$ = $a^{z-x}$