evalute both.................
Attachments:
Answers
Answered by
1
x^2(x-2)/(x-3)(x-2)
(x^2)/x-3
substitute x=2
2*2/2-3
4/-1
=-4
2). 2cos^2 x -1 = cos 2x
2cos^2 x -2 = cos 2x-1
2(cos^2 x -1 ) = cos 2x-1
now substitute in given equation
= 2(cos^2 x -1)/ cosx-1
= 2(cosx +1)(cosx -1)/ cosx-1
= 2(cosx+1)
= 2(cos(0)+1)
= 2(1+1) =2*2
= 4
(x^2)/x-3
substitute x=2
2*2/2-3
4/-1
=-4
2). 2cos^2 x -1 = cos 2x
2cos^2 x -2 = cos 2x-1
2(cos^2 x -1 ) = cos 2x-1
now substitute in given equation
= 2(cos^2 x -1)/ cosx-1
= 2(cosx +1)(cosx -1)/ cosx-1
= 2(cosx+1)
= 2(cos(0)+1)
= 2(1+1) =2*2
= 4
Answered by
3
Answer:
x^2(x-2)/(x-3)(x-2)
(x^2)/x-3
substitute x=2
2*2/2-3
4/-1
=-4
2). 2cos^2 x -1 = cos 2x
2cos^2 x -2 = cos 2x-1
2(cos^2 x -1 ) = cos 2x-1
now substitute in given equation
= 2(cos^2 x -1)/ cosx-1
= 2(cosx +1)(cosx -1)/ cosx-1
= 2(cosx+1)
= 2(cos(0)+1)
= 2(1+1) =2*2
= 4
Step-by-step explanation:
Similar questions