Math, asked by pavani5559, 2 months ago

evalute each of the following using suitable identities (104)³. (999)³.​

Answers

Answered by GargiRana
3

Answer:

(1) (104)

3

=(100+4)

3

[Now (a+b)

3

=a

3

+3a

2

b+3ab

2

+b

3

]

=(100)

3

+3(100)

2

(4)+3(100)(4)

2

+4

3

=1000000+3×10000×4+3×100×16+64

=1000000+120000+4800+64

=1124864

(2) (999)

3

=(1000−1)

3

(a−b)

3

=a

3

−3a

2

b+3ab

2

−b

3

=(1000)

3

−3(1000)

2

(1)+3(1000)(1)

2

−(1)

3

=1000000000−3×1000000+3×1000−1

=997,002,999

Step-by-step explanation:

Hope it helps you....❤️

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