evalute each of the following using suitable identities (104)³. (999)³.
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Answer:
(1) (104)
3
=(100+4)
3
[Now (a+b)
3
=a
3
+3a
2
b+3ab
2
+b
3
]
=(100)
3
+3(100)
2
(4)+3(100)(4)
2
+4
3
=1000000+3×10000×4+3×100×16+64
=1000000+120000+4800+64
=1124864
(2) (999)
3
=(1000−1)
3
(a−b)
3
=a
3
−3a
2
b+3ab
2
−b
3
=(1000)
3
−3(1000)
2
(1)+3(1000)(1)
2
−(1)
3
=1000000000−3×1000000+3×1000−1
=997,002,999
Step-by-step explanation:
Hope it helps you....❤️
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