Question

evalute each of the following using suitable identities.
a.(103)^3
b.102×105​

Answer 1

Answer:

b ) 102 ×105 = 10710

a) 103 × 3 = 903

Answer 2

Step-by-step explanation:

a)

(a+b)³ = a³+b³+3ab(a+b)

(100+3)³ = 100³+3³+3×100×3(100+3)

= 1000000+27+900×103

= 1000000+27+92700

= 1092727

B)

Hi there !!

Given,

to evaluate using algebraic identity,

the product of 105 × 102

105 can be written as 100 + 5

102 can be written as 100 + 2

so,

105 × 102 = (100 + 5)(100 + 2)

the following product (100 + 5)(100 + 2) is in the form of identity (x + a)(x + b) = x² + x(a + b) + ab

Substituting the values,

we have,

(100)² + 100(5 + 2) + 5×2

= 10000 + 700 + 10

= 10710

Thus, 105 × 102 is 10710