Question

Evalute integral In0/2 sin xdx​

Answer 1

Answer:

sorry

Explanation:

i don't intrest sorry

Answer 2

Using the definition of the integral and the fact that sinx is an odd function, from 0 to 2π ,with equal area under the curve at

[0,π] and above the curve at [π,2π] , the integral is 0.

This holds true for any time sin x

is evaluated with an integral across a domain where it is symmetrically above and below the x-axis.

∫ 2π0sinxdx=[−cosx] ∣∣∣2π0=−cos2π

−(−cos0)=−1−(−1)=0