Math, asked by shahinsheikh084, 1 year ago

evalute it plzzzzzzz nd solve it

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Answered by Ramanujmani
5
heya...!!!!


lim \frac{ \sqrt{3 + x} -  \sqrt{5 - x}  }{ {x}^{2} - 1 }  \\ x -  > 1 \\  \\  =  > lim \frac{ \sqrt{3 + x} -  \sqrt{5 - x}  }{ {x}^{2} - 1 }  \times  \frac{(\sqrt{3 + x}  +   \sqrt{5 - x}  )}{(\sqrt{3 + x}  +  \sqrt{5 - x}  )}  \\ x -  > 1  \\  \\  =  > lim \frac{ {3 + x} -  {5  +  x}  }{( {x}^{2} - 1)(\sqrt{3 + x}  +   \sqrt{5 - x}  )}  \\ x -  > 1 \\  \\ lim \frac{2(x - 1)}{(x - 1)(x + 1)( \sqrt{3 + x} -  \sqrt{5 - x} ) }  \\  x-  > 1 \\  \\  =  > lim \frac{2}{(1 + 1)( \sqrt{3 + 1} + \sqrt{5 - 1}) }  \\ x -  > 1 \\  \\  =  > lim \frac{2}{2 \times (2 + 2)} \\ x -  > 1  \\  \\  =  >  \frac{1}{4}
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