Evalute sec 35 degree /cosec 55 degree
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Answered by
11
Sec35=1/cos35
Cosec35=1/sin35
That implies Sec35/cosec35=sin35/cos35
=tan35
Cosec35=1/sin35
That implies Sec35/cosec35=sin35/cos35
=tan35
Answered by
25
=sec(90-55)/cosec55
=cosec55/cosec55
=1
=cosec55/cosec55
=1
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