Question

evalute:
Sin(40+theta)cos(10+theta)-cos(40+theta)sin(10+theta)

Answer 1

Answer:

sin(40+θ)cos(10+θ)-cos(40+θ)sin(10+θ)=

given is of the form

sinAcosB-cosAsinB=sin(A-B)

here A=40+θ, B=10+θ

So sin(40+θ-10-θ)------Equation 1

    =sin30=1/2

   LHS=RHS

 

and from equation 1 we can observe that θ can take any value(there exists infinite values of θ )

Hope this helped you.....................

Read more on Brainly.in - https://brainly.in/question/1247973#readmore