Question

evalute (sin teta +cos teta) square +(cos teta +sin teta ) square​

Answer 1

Answer:

Given that sinθ+cosθ=1

now squaring both side we have

(sinθ+cosθ)

2

=1

2

sin

2

θ+cos

2

θ+2sinθcosθ=1

1+2sinθcosθ=1 (sin

2

θ+cos

2

θ=1)

2sinθcosθ=0

sin2θ=0 (sin2θ=2sinθcosθ)

Hope it is helpful to

Answer 2

$\bold \orange{answer}$