Math, asked by acceptroshan3128, 7 months ago

Evalute sin30°+tan45°-cosec60°÷cot45°+cos60°-sec30°

Answers

Answered by PharohX
5

Answer:

 \frac{sin30°+tan45°-cosec60°}{cot45°+cos60°-sec30°}  \\  \\  \frac{ \frac{1}{2}  + 1 -  \frac{2}{ \sqrt{3} } }{1 +  \frac{1}{2} -  \frac{2}{ \sqrt{3} }  }   \\  =  \frac{ \frac{3}{2}  -  \frac{2}{ \sqrt{3} } }{ \frac{3}{2}  -  \frac{2}{ \sqrt{3} } }  \\  = 1 \\ ans...

Answered by pradeepunninair
0

Answer:

-0.30

Step-by-step explanation:

Sin30=0.5

Tan45=1

Cosec60=1.15

Cot45=1

Cos60=0.5

Sec30=1.15

Total 0.5+1-1.15/1+0.5-1.15

=2-2.3=-0.30

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