evalute the limit of (viii)
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lim h->0 loga(x+h) - logax/h. ......(1)
we know that
d[f(x)]/dx = lim h->0 f(x+h) - f(x)/h. ...(2)
on comparing eqn (1) and (2) we get
f(x) = loga(x)
so
f'(x) = d[loga(x)]/dx
= 1/x loge(a) (by using the property of log)
:')
we know that
d[f(x)]/dx = lim h->0 f(x+h) - f(x)/h. ...(2)
on comparing eqn (1) and (2) we get
f(x) = loga(x)
so
f'(x) = d[loga(x)]/dx
= 1/x loge(a) (by using the property of log)
:')
alex57:
thank u again
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