Question

Evalute the sum [(27/8)^2÷(81/4)^3]×6^4
pls tell me fast the ans with method plss
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Answer 1

Answer:

${( \frac{27}{8} )^{2} \div ( \frac{81}{4} ) ^{3} } \times {6}^{4}$

$\frac{27}{4} \times \frac{27}{4} \times \frac{4}{81} \times \frac{4}{81} \times \frac{4}{81} \times {6}^{4}$

$\frac{1}{3} \times \frac{1}{3} \times \frac{4}{81} \times \frac{4}{81} \times 6 \times 6 \times 6 \times 6$

$\frac{4 \times 4 \times 4 \times 6 \times 6}{81 \times 81}$

$\frac{4 \times 4 \times 4 \times 4}{27 \times 27}$

$\frac{64}{729}$

Hope it helps...

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