Question

evalute using identity (999)2​

Answer 1

Answer:

${999}^{2}$

$( {1000} - {1})^{2}$

$acc \: to \: ({x} - {y})^{2} = {x}^{2} + {y}^{2} - 2xy$

${1000}^{2} + {1}^{2} - 2 \times 1000 \times 1$

$1000000 + 1 - 2000$

$998001$