Evaluvate integral of |x+3|dx with lower limit as -6 and upper limit as 0
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integral of |x+3|dx with lower limit as -6 and upper limit as 0
= integral of (x+3) dx with lower limit as -3 and upper limit as 0 +integral of (-x-3)dx with lower limit as -6 and upper limit as -3
=(x^2 + 3x) with lower limit as -3 and upper limit as 0 -(x^2+3x) with lower limit as -6 and upper limit as -3
= 0 + 0 - (9 - 9) - (9 - 9) + (36 - 18) = 18
= integral of (x+3) dx with lower limit as -3 and upper limit as 0 +integral of (-x-3)dx with lower limit as -6 and upper limit as -3
=(x^2 + 3x) with lower limit as -3 and upper limit as 0 -(x^2+3x) with lower limit as -6 and upper limit as -3
= 0 + 0 - (9 - 9) - (9 - 9) + (36 - 18) = 18
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