Math, asked by shanif23, 10 months ago

evalvate sin 18°÷cos 72°​

Answers

Answered by shubum3199
3

sin18/cos72

sin(90-72)/cos72

sin72/cos72

1

ans is 1

Answered by Kaustav26
7

sin18° ÷ cos72°

= sin18° ÷ cos(90-18)°

= sin18° ÷ sin18° {cos(90-θ)=sinθ}

= (sin18°/sin18°)

= 1

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