Question

Evan has two baskets containing snacks items. The first basket contains one package each of peanuts, almonds, cashews, and pretzels. The second basket contains a banana, a mango, a peach, a pear, and a plum. Evan takes one item from the first basket and two items from the second basket for his lunch. If Evan takes either the package of peanuts or the banana, how many different selections of three snack items can he take? A. 18 B. 22 C. 36 D. 40

Answer 1

Given:

There are two baskets. One of them contains peanuts, almonds, cashews and pretzels one package each and the other basket has a banana, a mango, a peach, a pear and a plum.

To Find:

If Evan takes one item and two items from the first and second basket respectively then, find the number of different selections of three items can be made.

Step-by-step explanation:

The first basket contains peanuts, almonds, cashews and pretzels one package each.

So, there are four items which can be picked in 4 ways if any one of them is picked at a time.

The second basket is containing a banana, a mango, a peach, a pear and a plum.

So, if any 2 of those 5 items if picked randomly then possible number of different selections will be $^5C_2 = 10$.

Therefore, the number of different selections of three items will be $= 4\times 10 = 40$