Evaulate using an algebraic identity the product 103 X 97
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103 × 97.
=(100+3)×(100-3)
=(100)^2 - 3^2 [using identity a^2 - b^2 =(a+b)(a-b)
=10000 - 9
= 9991
=(100+3)×(100-3)
=(100)^2 - 3^2 [using identity a^2 - b^2 =(a+b)(a-b)
=10000 - 9
= 9991
Answered by
5
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