Question

even figure,
be given figure, ZTP
TPQ = 111° and ZTRS = 164º. Find the value of x.​

Answer 1

Explanation:

so angle QPR =180-111 = 69°

and angle PRQ=180-164 = 16°

x is exterior angle of triangle PQR.

Therefore x=16+69° =85°. because exterior angle is equal to sum of opposite interior angles.

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Answer 2

Answer:

Sol: By linear pair property of angle;

TPQ +RPQ =180°

111° + RPQ = 180°

RPQ = 180° - 111°

RPQ = 69°

Again ,By linear pair property of angle ;

PRQ + PRS = 180°PRQ + 164° =180°

PRQ = 180° - 164°

PRQ = 16°

NOW, In PQR ,By Exterior angle property of triangle ;

Exterior angle = Sum of opposite interior angle

UQS = RPQ + PRQ

X = 69° + 16°

X = 85°