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ii)The vertices of the triangle:
B(-3,0) ; C(3,0)
i)Here m₁ & m₂ are ratio of the line BC. The formula of finding the midpoints:
(m₁x₂-m₂x₁)÷(m₁+m₂) = ((1×3)-(1×-3))÷(1+1) = 3-3÷2 = 0÷2 = 0
Anonymous:
hi nandu
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