Every biscuit pack contains 12 biscuits. Alex has 3 full packs and another hall such pack. He gave 9 biscuits to Ayub and 5 biscuits to
Anand. How many packs are remaining with Alex?
Answers
Answered by
11
Answer:
he have 3 1/2 packs of biscuit
therefore total no. of biscuits is 42
biscuits left after giving it to ayub and Anand
=42-9-5
=28
packs left=28/12
=2 1/3 packs
please mark BRAINLIEST
Answered by
2
Answer:
\\frac{2}{3}
Step-by-step explanation:
Each pack of biscuits contains 12 biscuits.
Alex had 3 and half of a pack, which is same as 3
\\frac{1}{2}
\\frac{7}{2}
.
He gave 2 packs and 10 biscuits to Ayub, that is he gave 2
\\frac{10}{12}
or
\\frac{34}{12}
.
\\frac{7}{2} − \\frac{34}{12}
To subtract we need to make the denominators equal.
The Least Common Multiple (or LCM) is 12.
\frac{7*6}{2*6} - \frac{34*1}{12*1}
\\frac{42}{12} − \\frac{34}{12}
\\frac{8}{12}
\frac{8/4}{12/4}
\\frac{2}{3}
Hence, Alex is left with \\frac{2}{3} of biscuit packs.
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