Math, asked by shwetaranjan009, 11 months ago


Every biscuit pack contains 12 biscuits. Alex has 3 full packs and another hall such pack. He gave 9 biscuits to Ayub and 5 biscuits to
Anand. How many packs are remaining with Alex?​

Answers

Answered by madhutiwari793
11

Answer:

he have 3 1/2 packs of biscuit

therefore total no. of biscuits is 42

biscuits left after giving it to ayub and Anand

=42-9-5

=28

packs left=28/12

=2 1/3 packs

please mark BRAINLIEST

Answered by jumtamil
2

Answer:

\\frac{2}{3}

Step-by-step explanation:

Each pack of biscuits contains 12 biscuits.

Alex had 3 and half of a pack, which is same as 3

\\frac{1}{2}

\\frac{7}{2}

.

He gave 2 packs and 10 biscuits to Ayub, that is he gave 2

\\frac{10}{12}

or

\\frac{34}{12}

.

\\frac{7}{2} \\frac{34}{12}

To subtract we need to make the denominators equal.

The Least Common Multiple (or LCM) is 12.

\frac{7*6}{2*6} - \frac{34*1}{12*1}

\\frac{42}{12} \\frac{34}{12}

\\frac{8}{12}

\frac{8/4}{12/4}

\\frac{2}{3}

Hence, Alex is left with \\frac{2}{3} of biscuit packs.

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