Every finite integral domain is a field
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To prove :
A finite integral domain is a field .
Proof :
Let D be a finite integral domain with unity 1 . Let a be any non-zero element of D , then we must show that a is a unit .
If a = 1 , a is its own inverse , so we may assume that a ≠ 1 .
Now , consider the following sequence of elements of D : a , a² , a³ , . . .
Since D is finite , there must be two positive integers m and n such that m > n and aᵐ = aⁿ .
Then by cancellation , aᵐ⁻ⁿ = 1 .
Since a ≠ 1 , m - n > 1 .
Now ,
Let b ≠ 0 the inverse of a , then ab = ba = 1 .
→ ab = 1
→ ab = aᵐ⁻ⁿ (°•° aᵐ⁻ⁿ = 1)
→ b = aᵐ⁻ⁿ⁻¹
Thus , we have shown that aᵐ⁻ⁿ⁻¹ is inverse of a .
Hence , D is a field .
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