every sublattice of modular lattice is modular prove
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PROOF: 1. The diamond is modular, but not distributive. ... The diamond is not distributive: y ∨ (x ∧ z) = y (y ∨ x) ∧ (y ∨ z) = 1 The class of distributive lattices is defined by identity 5, hence it is closed under sublattices: every sublattice of a distributive lattice is itself a distributive lattice.
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