Question

Every time x is increased by a given constant number, y doubles and z
becomes three times. How will log(y) and log(z) behave as x is increased by
the same constant number?​

Answer 1

Answer:

y₂/y₁ = 2  

log(y₂/y₁) = log(2)  

log(y₂) - log(y₁) = log(2) = constant  

log(y) increases linearly ---> ∆log(y)/∆x = log(2)/k  

z₂/z₁ = 3  

log(z₂/z₁) = log(3)  

log(z₂) - log(z₁) = log(3) = constant  

log(z) increases linearly ---> ∆log(z)/∆x = log(3)/k  

Step-by-step explanation:

Answer 2

Given; Every time x is increased by a given constant number, y doubles  and z

becomes three times

To Find; How will log(y) and log(z) behave as x is increased by the same constant number

Solution; y2/y1= 2

log(Y2/y1)=log2

logy2-logy1= log2

log y increases linearly

z2/z1=3

logz2-logz1=log3

log z increases linearly.

Hence both logy and logz increases lineraly.

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