Question

Every year, on his birthday, David shares $300 among his children in the ratio of their ages.
This year the children are aged 4,9 and 11.
How much less will the oldest child receive in two years' time, than in this year?​

Answer 1

Given:

Total money = $300

Children present ages are 4, 9 and 11

To find:

How much less will the oldest child receive in two years' time, than in this year?​

Solution:

Present year:

Oldest child receives = $\frac{11}{4+9+11} *300$

Oldest child receives = 11 / 24 * 300 = $137.5

After two years:

Ages after two years are 6, 11 and 13

Oldest child receives = $\frac{13}{6+11+13} * 300$

Oldest child receives = 13 / 30 * 300 = $130

Difference = $137.5 - $130 = $7.5

Therefore, the oldest child receives $7.5 less after two years.