Question

everybody is getting ready for the party change into past indefinite​

Answer 1

Answer:

༒ Bʀᴀɪɴʟʏ Sᴛᴀʀs

༒Mᴏᴅʀᴀᴛᴇʀs

\huge \mathfrak{ \red{Qu} \green{e} \pink{s} \blue{t} \purple{ion}}Question

If

\begin{gathered} \large\bf \int \frac{dx}{( {x}^{2} - 2x + 10) ^{2} } \\ \\ = \bf A \bigg \{{tan}^{ - 1} \bigg( \frac{x + 1}{3} \bigg) + \frac{f(x)}{ {x}^{2} - 2x + 10} \bigg \} + C\end{gathered}

∫

(x

2

−2x+10)

2

dx

=A{tan

−1

(

3

x+1

)+

x

2

−2x+10

f(x)

}+C

Then ➽

\begin{gathered} \bf a)A = \frac{1}{27} \: and \: f(x) = 9(x - 1) \\ \\ \bf b)A = \frac{1}{81} \: and \: f(x) = 3(x + 1) \\ \\ \bf c)A = \frac{1}{54} \: and \: f(x) = 3(x - 1) \\ \\ \bf d)A = \frac{1}{54} \: and \: f(x) = 9(x - 1) {}^{2} \end{gathered}

a)A=

27

1

andf(x)=9(x−1)

b)A=

81

1

andf(x)=3(x+1)

c)A=

54

1

andf(x)=3(x−1)

d)A=

54

1

andf(x)=9(x−1)

2

Answer 2

Answer:

everybody was getting ready for the party