Question

evision
20. The present ages of two brothers are in the ratio 4:3. Nine years hence their ages will be in the ratio
23:18. Find their
[Ans. 60 years, 45 years]
present
ages.
​

Answer 1

Ans.

60 years and 45 years

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Answer 2

Answer:

let present ages be 4x and 3x

nine year hence their ages will be =4x+9 & 3x+9

((4x+9)/(3x+9))=23/18

18(4x+9)=23(3x+9)

72x+162=69x+207

3x=45

x=15

so present ages will be 4x=4×15=60 & 3x=3×15=45