Question

evulate (x^a-b)^a+b (x^b-c)^b+c ×(x^c-a)^c+a​

Answer 1

Answer:

Step-by-step explanatio

xa-b)a+b (xb-c)b+c (xc-a)c+a  = x(a-b)(a+b) x(b-c)(b+c) x(c-a)(c+a)  = xa²-b² xb²-c² xc²-a²  ∵ (a + b)(a – b) = a2 – b2  = xa²-b²+b²-c²+c²-a²  = x0  = 1