Question

Ex. 1.15.6
Fringes of equal thickness are observed in a thin glass
wedge of refractive index 1.52. The fringe spacing is 1 mm
and the wavelength of light is 5893 Aº. Calculate the angle
of wedge in seconds of an arc.​

Answer 1

Answer:

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Answer 2

$\pi$Answer:

the angle of wedge in seconds of an arc is 40 sec.

Explanation:

• given,

              μ =1.52, '

              λ = 5893 x10−8 cm,

            Dx =0.1 cm

• we know the basic formula ,

                   $Dx=$ λ / μθ

• substitute all the values and finding θ,

                  θ $=$ λ /$2$μ$Dx$  $radians$

                   θ$= 5893$ x $10^{-8}$ / $2$ x $1.52$ x $0.1$

                     $=$ $1.93$ x $10^{-4}$  $radians$.

• but, here we want to find  angle in seconds ,

                   ∴ $\pi$ $radians$  ⇒ $180^{0}$

                   $1.93$ x $10^{-4}$ $radians$ ⇒ ?

                   θ $=$ $1.93$ x $10^{-4}$ x $180$  / $\pi$

                     $=$ $40$ seconds of an arc.