Question

Ex. 10. A copper bar carrying 1000 A has a potential
drop 1m V along 10 cm of its length. What is the resistance
per minute of the bar?
V
103​

Answer 1

Given : A copper bar carrying 1000 A has a potential  drop 1m V along 10 cm of its length.

To Find : What is the resistance  per meter of the bar?

Solution:

Current  = 1000 A

Voltage Drop = 1 mV

Resistance = Voltage / Current

=> Resistance = 1 mV / 1000 A

=> Resistance =10⁻³  V / 10³ A

=> Resistance = 10⁻⁶ Ω

Resistance = 10⁻⁶ Ω  

Length of Copper Bar = 10 cm  = 10/100 = 1/10 m

=>  Resistance = 10⁻⁶ Ω   per  1/10 m

resistance  per meter of the bar =  10 * 10⁻⁶ Ω per m

= 10⁻⁵ Ω per m  

or 10 μΩ per m  

resistance  per meter of the bar = = 10⁻⁵ Ω per m

10 μΩ per m  

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