Question

ex 12.2 class 10 ncert q 6​

Answer 1

Step-by-step explanation:

6. A chord of a circle of radius 15 cm subtends an angle of at the centre. Find the area of the corresponding minor and major segment of the circle.

Ans. Here, = 15 cm and

Area of minor sector=

=

=

For, Area of AOB,

Draw OMAB.

In right triangles OMA and OMB,

OA = OB [Radii of same circle]

OM = OM [Common]

OMA OMB [RHS congruency]

AM = BM [By C.P.C.T.]

AM = BM = AB and

AOM = BOM = AOB =

In right angled triangle OMA,

OM = cm

Also,

AM = cm

2 AM = = 15 cm

AB = 15 cm

Area of AOB =

= =

= =

Area of minor segment = Area of minor sector – Area of AOB

= 117.75 – 97.3125 =

And, Area of major segment = Area of minor segment

= 3.14 x 15 x 15 - 20.4375 = 706.5 – 20.4375 =