Question

Ex. 2.1.4: Force between two equal and similar charges
is 5 N when they are placed in air at certain distance. What
will be the force between them if the distance between them
is doubled ?​

Answer 1

horse between two equal charges 5N at certain distance

F=kq1q2/r2=5N

distance doubled then

F=kq1q2/(2r)2

=kq1q2/4r2

=5/4N

=1.25N