Physics, asked by shakti34, 1 year ago


Ex. 2. A body weighs 500 gf in air and 450 gf when wholly immersed in water. Calculate :
(i) the loss in weight of the body in water.
(ii) the upthrust of the body.
(iii) volume of the body​

Answers

Answered by aayurya
3

Answer:

Weight of body in air,W=450gf=450g dynes

Weight of body in water,W =310gf=310g dynes

Let d be the density of the body,v be the volume .

Let q be the density of water.

Now,

W=Vdg

-->450 g =Vdg

Buoyant force , B =Vgq

-->B= Vg[q=1g/cm3]

Now, W/=W-B

-->310g = 450g-Vg

-->v =140 cm3

Loss in weight =Buoyant force = Vqg=140×1×g=140g dynes

=140gf

Again upthrust =Buoyant force = 140 gf

Hope it helps...

Answered by ssoniakapoor
2

Answer: 50 gf

Explanation: body weighs in air        = 500 gf

                      body weighs in water  = 450 gf

                      lose of weight in water = 500 - 450 = 50 gf

i know the answer of only first,sorry for the inconvience

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