Ex. 2. A body weighs 500 gf in air and 450 gf when wholly immersed in water. Calculate :
(i) the loss in weight of the body in water.
(ii) the upthrust of the body.
(iii) volume of the body
Answers
Answered by
3
Answer:
Weight of body in air,W=450gf=450g dynes
Weight of body in water,W =310gf=310g dynes
Let d be the density of the body,v be the volume .
Let q be the density of water.
Now,
W=Vdg
-->450 g =Vdg
Buoyant force , B =Vgq
-->B= Vg[q=1g/cm3]
Now, W/=W-B
-->310g = 450g-Vg
-->v =140 cm3
Loss in weight =Buoyant force = Vqg=140×1×g=140g dynes
=140gf
Again upthrust =Buoyant force = 140 gf
Hope it helps...
Answered by
2
Answer: 50 gf
Explanation: body weighs in air = 500 gf
body weighs in water = 450 gf
lose of weight in water = 500 - 450 = 50 gf
i know the answer of only first,sorry for the inconvience
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