Question

Ex.25.
Mr. Kumar drives to work at an average
speed of 48 km/hr. The time taken to
cover the first 60% of the distance is 10
min more than the time taken to covers
the remaining distance. How far is his
office?
(A) 30 km (B) 40 km.
(C) 45 km. (D) 48 km​

Answer 1

Answer:

Mr Kumar drive 48 kilometres per hour the time taken covered the first 60% in 10 minutes

find more than time taken to cover the remaining distance. 100%-60%

=40%

48km /hr ÷60%

=48÷60%

=28.8

=28.8 ×10

=2.88 km (a)

and

and the remaining distance is 40%

=40%×30

=12

=12÷10

= 1.2

=1.2 km (b)

the total distance a+b

=. 2.88 km +1.2 km

=4.8 km

the total distance is 4.8 km

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