Math, asked by anshugosai6, 9 months ago

Ex. 27. Find the remainder when 2^31 is divided by 5.​

Answers

Answered by AtTiTuDeQuEeN15
0

Answer:

here is ur answer...

Step-by-step explanation:

Now,231=228×23.So,it is equivalent to finding the remainder when 23 is divided by 5..which is 3.So,the remainder when 231 is divided by 5 is 3..

Answered by indu2380
0

Step-by-step explanation:

2^1 = 2

2^2 = 4

2^3 = 8

2^4 = 16

2^5 = 32

2^6 = 64

here you can see the unit’s place of every fourth no repeats.

getting back to 2^(31) divided by 5.

First off, we take the power, i.e. 31, and divide it by the the base number, i.e. 2 in this case.

=>31/4 gives a remainder of 3. So now, we take the remainder obtained on division and place that as the power.

=>23/5=8/5−−−> gives a remainder of 3, which is the required answer.

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