Ex. 27. Find the remainder when 2^31 is divided by 5.
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Answer:
here is ur answer...
Step-by-step explanation:
Now,231=228×23.So,it is equivalent to finding the remainder when 23 is divided by 5..which is 3.So,the remainder when 231 is divided by 5 is 3..
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Step-by-step explanation:
2^1 = 2
2^2 = 4
2^3 = 8
2^4 = 16
2^5 = 32
2^6 = 64
here you can see the unit’s place of every fourth no repeats.
getting back to 2^(31) divided by 5.
First off, we take the power, i.e. 31, and divide it by the the base number, i.e. 2 in this case.
=>31/4 gives a remainder of 3. So now, we take the remainder obtained on division and place that as the power.
=>23/5=8/5−−−> gives a remainder of 3, which is the required answer.
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