Question

Ex 3.3 Class 6 Maths Question 5.
Write the smallest digit and the greatest digit in the blank space of each of the following numbers so that the number formed is divisible by 3.
(a) ____ 6724
(b) 4765 ____ 2​

Answer 1

Answer:

Solution:

We know that number is divisible by 3 if the sum of all the digits of the number is also divisible by 3.

(a) ___ 6724

Sum of the digits = 4 + 2 + 7 + 6 = 19

The smallest digit to be placed is blank space = 2

Then the sum = 19 + 2 = 21 which is divisible by 3.

The greatest digit to be placed in blank space = 8

Then, the sum = 19 + 8 = 27 which is divisible by 3

Hence, the required digits are 2 and 8.

(b) 4765 ____ 2.

Sum of digits = 2 + 5 + 6 + 7 + 4 = 24

The smallest digits to be place in blank space = 0

Then, sum = 24 + 0 = 24

which is divisible by 3.

The greatest digit to be placed in blank space = 9.

Then, the sum = 24 + 9 = 33 which is divisible by 3.

Hence, the required digits are 0 and 9.