Question

Ex-4.3 Q6 10th Class​

Answer 1

Answer:

Let us say, the shorter side of the rectangle be x m.

Then, larger side of the rectangle = (x + 30) m

Ncert solutions class 10 chapter 4-6

As given, the length of the diagonal is = x + 30 m

Therefore,

Ncert solutions class 10 chapter 4-7

⇒ x2 + (x + 30)2 = (x + 60)2

⇒ x2 + x2 + 900 + 60x = x2 + 3600 + 120x

⇒ x2 – 60x – 2700 = 0

⇒ x2 – 90x + 30x – 2700 = 0

⇒ x(x – 90) + 30(x -90) = 0

⇒ (x – 90)(x + 30) = 0

⇒ x = 90, -30